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3 June, 17:17

To what pressure would you have to compress 48.0 L

of oxygen gas at 99.3 kPa in order to reduce its vol-

ume to 16.0 L?

+1
Answers (1)
  1. 3 June, 17:36
    0
    298 kPa

    Explanation:

    Data Given:

    initial Volume of oxygen V1 = 48.0 L

    Final Volume of oxygen V2 = 16.0 L

    initial pressure of oxygen P1 = 99.3 kPa

    initial Pressure of oxygen P2=?

    Solution:

    The Boyle's law formula will be applicable here at constant temperature

    Boyle's law formula

    P1V1 = P2V2

    As we have to find final pressure so rearrange the equation

    P2 = P1V1 / V2 ... (1)

    Put values in Equation 1

    P2 = 99.3 kPa x 48 L / 16 L

    P2 = 298 kPa

    So the final pressure will be 298 kPa
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