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9 March, 04:59

The pressure of 6.0 L of a gas is 200 kPA. What will be the volume of the pressure is doubled, keeping the temperature constant?

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  1. 9 March, 05:28
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    3. 0 L

    Explanation:

    We'll use P₁V₁/T₁ = P₂V₂/T₂

    Because T₁ and T₂ are constant throughout, then the two cancel out and we are left with;

    P₁V₁ = P₂V₂

    We can bow replace the variables with given values form the question;

    200 * 6.0 = 400 * V₂

    200 * 6 / 400 = V₂

    3 = V₂

    = 3.0 L
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