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18 December, 08:00

A given mass of air has a volume of 6.00 L at 101 kPa. At constant temperature, the pressure is decreased to 25.0 kPa. Calculate the final volume for the gas, as described by Boyle's law.

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  1. 18 December, 08:09
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    24.24 L

    Explanation:

    Boyle's law, also called Mariotte's law, a relation concerning the compression and expansion of a gas at constant temperature.

    This empirical relation, formulated by the physicist Robert Boyle in 1662, states that the pressure (p) of a given quantity of gas varies inversely with its volume (v) at constant temperature; i. e., in equation form, pv = k, a constant.

    Real gases obey Boyle's law at sufficiently low pressures, although the product pv generally decreases slightly at higher pressures, where the gas begins to depart from ideal behaviour.

    As, PV = k

    P₁ V₁ = P₂ V₂

    Given P₁ = 101 KPa

    V₁ = 6 L

    P₂ = 25 kPa

    So, V₂ = P₁ V₁ / P₂ = 101 * 6/25 = 24.24 L
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