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8 August, 11:57

Calculate the molar solubility of AgCl, using its Ksp value of 1.8 x 10-10.

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  1. 8 August, 12:01
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    Answer:1.34 * 10^-5

    Explanation:

    AgCl = (Ag+) (Cl-)

    = (S) (S)

    = S²

    S stands for molar solubility

    Ksp = S² = 1.80 * 10^ - 10

    S = √[1.80 * 10^ - 10]

    =1.34 * 10^-5
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