A titration was performed on 50.0mL of 0.250 M NaOH. After the

addition of 7.14mL of HCI, the phenolpthalein indicatorchanged from

pink to colorless. What was the concentration ofthe hydrochloric

acid?

1.750 M

Explanation:

In case of titration, the following formula can be used -

M₁V₁ = M₂V₂

where,

M₁ = concentration of acid,

V₁ = volume of acid,

M₂ = concentration of base,

V₂ = volume of base.

from, the question,

M₁ = ? M

V₁ = 7.14 mL

M₂ = 0.250 M

V₂ = 50 mL

Using the above formula, the molarity of acid, can be calculated as,

M₁V₁ = M₂V₂

M₁ * 7.14 mL = 0.250 M * 50mL

M₁ = 1.750 M

Hence, the molarity of the hydrochloric acid = 1.750 M