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23 May, 12:07

What is the specific heat (J/g C) of a metal who's temp increases by 3.0 C when 17.5 g of metal was heated with 38.5 J

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  1. 23 May, 12:23
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    0.733 J/g °C

    Explanation:

    Step 1 : Write formule of specific heat

    Q = mc Δ T

    with Q = heat transfer (J)

    with m = mass of the substance

    with c = specific heat ⇒ depends on material and phase (J/g °C)

    Δ T = Change in temperature

    in this case:

    Q = 38.5 J

    m = 17.5g

    c = has to be determined

    Δ T = 3 (°C)

    Step 2: Calculating specific heat

    ⇒ via the formule Q = mc Δ T

    38.5 J = 17.5g * c * 3

    38.5 = 52.5 * c

    c = 38.5 / 52.5

    c = 0.733 J/g °C ⇒ 0.733 is reported to three significant digits due to the precision.

    The specific heat of this metal is 0.733 J/g °C
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