What is the volume of 10.0 g of argon gas at 157°c and 2.50 kpa pressure?

Data Given:

Pressure = P = 2.5 kPa = 0.02467 atm

Temperature = T = 157 °C + 273.15 = 430.15 K

Volume = V = ?

Mass = m = 10 g

First find out moles for given amount of Argon gas,

As,

Moles = Mass / M. mass

Putting values,

Moles = 10 g / 39.94 g/mol = 0.250 moles

Now using Ideal Gas Equation,

P V = n R T

Solving for V,

V = n R T / P

Putting Values,

V = (0.25 mol * 0.0821 L. atm. mol⁻¹. K⁻¹ * 430.15 K) : 0.02467 atm

Volume = 357.87 L