How many calories are given off by 85 g of water that cools from 90 c to 67 c?

Q = - 1.95 kCal

Solution:

The equation used for this problem is as follow,

Q = m Cp ΔT

Where'

Q = Heat = ?

m = mass = 85 g

Cp = Specific Heat Capacity = 4.18 J. g⁻¹.°C⁻¹

ΔT = Change in Temperature = 67 °C - 90 °C = - 23 °C

Putting values in eq. 1,

Q = 85 g * 4.18 J. g⁻¹.°C⁻¹ * - 23 °C

Q = - 8172 J

Q = - 1.95 kCal