How many total atoms are in 0.210 g of P2O5?

Question

Bennett Ward

Chemistry

5 May, 22:58

How many total atoms are in 0.210 g of P2O5?

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Answers (1)

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Clinton Bender · Answer 1

M (P 2 O 5) = 0.210 g

M (P 2 O 5) = 2 * 30 + 5 * 16 (from the Periodic Table) =

= 60 + 80 = 140 g/mol

N = m / M = 0.210 g / 140 g/mol = 0.0015 mol

Avogadro Constant: N a = 6.02 * 10^23

n = N * N a = 0.0015 * 6.02 * 10^23 =

= 0.00903 * 10^23 = 9.03 * 10^20 atoms