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11 June, 14:59

When the partition is removed, the gas expands and fills both compartments. How many moles n of gas were initially contained in the lower compartment if the entropy change of the gas in this free-expansion process is 17.28 J/K

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  1. 11 June, 15:17
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    n = 1.89 mol.

    Explanation:

    Think of this as adiabatic free expansion. This means constant temperature - - we know this because the internal energy does not change.

    Since the temperature is constant, the entropy change can be given by:

    Entropy = nRln (V2/V1)

    Entropy = 17.28 J/K. R = 8.314 (gas constant). V2 = 3V. V1 = V.

    Thus, we get:

    17.28 = n (8.314) ln3

    Solve for n. We get n = 1.89 mol.
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