A 1.000 g sample of a metal chloride, MCl2, is dissolved in water and treated with excess aqueous silver nitrate. The silver chloride that formed weighed 1.286g. Calculate the atomic mass of M.

Given 1 gm of MCl2 fors 1.286g of AgClmolar mass of AgCl is 143.5 g 1.286g of AgCl contains 1.286/143.5 mols of AgCl = 0.0089616 molseach mol of MCl2 release two Cl - ionshence number of mols MCl2 given (1gm) is 0.0089616 / 2=0.0044808 mols hnce one mol of MCl2 weighs 1/0.0044808 = 223.17g