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26 August, 10:43

How many grams of the excess reactant remain assuming the reaction goes to completion and that you start with 15.5g of na2s and 12.1g cuso4?

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  1. 26 August, 11:08
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    First what is given to you?

    15.5 g of Na_2S

    12.1 g of CuSO_4

    Then decipher your formula ...

    g of Na_2S / g per mol of Na_2S / 1 mol = mol of Na_2S

    g of CuSO_4 / g per mol of CuSO_4 / 1 mol = mol of CuSO_4

    This will tell you which will react entirely with the elements. Then you should be able to determine which has excess amounts.

    Then with those answers - - - ((mol of Na_2S) - (mol of CuSO_4)) * (g per mol of Na_2S) = left over.

    (Hopefully that is clear. If not message me.)
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