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26 January, 20:31

The specific heat of aluminum is 0.125 cal/g °C. If 12.5 grams of aluminum were heated from 20.0 °C to 100.0 °C, calories of heat energy would be absorbed by the aluminum.

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  1. 26 January, 20:56
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    Aluminum does not undergo any phase change from 20.0°C to 100.0°C, therefore we only consider sensible heat change, which is calculate as

    q = mc (dT) q = (12.5 g) (0.125 cal/g-°C) (100 - 20) °C = 125 cal

    Therefore, 125 calories of heat are absorbed by the aluminum.
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