Calculate the percent composition of these compounds: (Ethane:C2H6) and (Sodium hydrogen sulfate: NaHSO4).

For the first compound,

Molar Mass of C=12.01x 2 = 24.02

Molar Mass of H = 1.01x 6 = 6.06

So molar mas of C2H6 = (12.01x2) + (1.01x6) = 30.08

To get the percent composition, the formula is " (Total MM of C in molecule) / (Total MM of molecule) x 100".

Here is the solution:

% of C = 24.02/30.08 x 100 = 79.9

% of H=6.06/30.08 x 100=20.1

To check if it is equal to 100%, you just have to add the percentages.

For the second compound,

Molar Mass of Na=22.99 x 1 = 22.99

Molar Mass of H = 1.01x 1 = 1.01

Molar Mass of S = 32.07x 1 = 32.07

Molar Mass of O = 16.00 x4 = 64.00

So molar mas of NaHSO4 = (22.99) + (1.01) + (32.07) + (16.00x4) = 120.07

To get the percent composition, the formula is " (Total MM of C in

molecule) / (Total MM of molecule) x 100".

Here is the solution:

% of Na = 22.99/120.07 x 100 = 19.2

% of H = 1.01/120.07x 100 = 0.8

% of S = 32.07/120.07x 100 = 26.7

% of O = 64/120.07 x 100 = 53.3

To check if it is equal to 100%, you just have to add the percentages.