For the reaction bro3 - + 5br - + 6h + → 3br2 + 3h2o at a particular time, - δ [bro3-]/δt = 1.5 * 10-2 m/s. what is - δ [br-]/δt at the same instant?

Question

Houston Rosales

Chemistry

31 March, 14:34

For the reaction bro3 - + 5br - + 6h + → 3br2 + 3h2o at a particular time, - δ [bro3-]/δt = 1.5 * 10-2 m/s. what is - δ [br-]/δt at the same instant?

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Emerson Shelton · Answer 1

The $ - (Br) at that instant is calculated as follows

BrO3 + 5Br - - - > 3Br2 + 3 H2o

by use of reacting ratio BrO3 to Br2 which is 1:3

therefore $ of Br = 3 x (1.5 x10^-2) = 4.5 x10^-2