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11 May, 13:09

12.5ml of 2.0m NaOH neutralizes 10ml og HCL, what is the acid concentration

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  1. 11 May, 13:14
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    2.5M

    Explanation:

    We begin by writing a balanced equation for the reaction. This is shown below:

    HCl + NaOH - > NaCl + H2O

    From the equation above we obtained the following:

    nA (mole of the acid) = 1

    nB (mole of the base) = 1

    Data obtained from the question include:

    Vb (volume of the base) = 12.5mL

    Mb (Molarity of the base) = 2M

    Va (volume of the acid) = 10mL

    Ma (Molarity of the acid) = ?

    The molarity of the acid can be calculated as follow:

    MaVa/MbVb = nA/nB

    Ma x 10 / 2 x 12.5 = 1

    Cross multiply to express in linear form as shown below:

    Ma x 10 = 2 x 12.5

    Divide both side by 10

    Ma = (2 x 12.5) / 10

    Ma = 2.5M

    The molarity of the acid is 2.5M
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