Solution X is 10 percent alcohol by volume, and solution Y is 30 percent alcohol by volume. How many milliliters of solution Y must be added to 200 milliliters of solution X to create a solution that is 25 percent alcohol by volume?

600 mL

Explanation:

The volume of 10% acid solution used to make the mixture = 200 L

Let the volume of 30% acid solution used to make the mixture = x mL

Total volume of the mixture = (200 + x) mL

For 10% acid solution:

C₁ = 10%, V₁ = 200 mL

For 30% acid solution:

C₂ = 30%, V₂ = x mL

For the resultant solution of sulfuric acid:

C₃ = 25%, V₃ = (200 + x) mL

Using

C₁V₁ + C₂V₂ = C₃V₃

10*200 + 30*x = 25 * (200 + x)

Solving for x,

x = 600 mL

600 milliliters of solution Y must be added to 200 milliliters of solution X to create a solution that is 25 percent alcohol by volume.