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17 October, 19:21

How many grams of O2 must be placed in a 3.33 liter container in order to exert a pressure of 2.46 atm at 27°C?

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  1. 17 October, 19:43
    0
    10.656 g

    Explanation:

    Given dа ta:

    Mass of oxygen = ?

    Volume of container = 3.33 L

    Pressure of gas = 2.46 atm

    Temperature = 27°C

    Solution:

    The given problem will be solve by using general gas equation,

    PV = nRT

    P = Pressure

    V = volume

    n = number of moles

    R = general gas constant = 0.0821 atm. L / mol. K

    T = temperature in kelvin

    Now we will convert the temperature.

    27+273 = 300 K

    Now we will put the values in formula.

    n = PV/RT

    n = 2.46 atm * 3.33 L / 0.0821 atm. L / mol. K * 300 K

    n = 8.192 atm. L / 24.63 atm. L / mol

    n = 0.333 mol

    Mass in grams:

    Mass = number of moles * molar mass

    Mass = 0.333 mol * 32 g/mol

    Mass = 10.656 g
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