Ask Question
12 June, 14:42

At a certain temperature, the ph of a neutral solution is 7.64. what is the value of kw at that temperature? express your answer numerically using two significant figures.

+1
Answers (1)
  1. 12 June, 14:54
    0
    It is very important to know that neutral pH changes with temperature. The key part to this problem is that the solution is neutral! In a neutral solution the pH and pOH are equal and therefor so are their concentrations. Kw = [H]*[OH] where [H] and [OH] represent the concentrations of those ions. pH=-log[H] antilog (-pH) = [H] Antilog is fancy way of saying 10^x. In our case x=-7.64 [H]=2.95 x 10^-8 M (Molarity) Since pH and pOH are equal in our neutral solution so are their concentrations. [OH]=2.95 x 10^-8 M Now we go back to Kw = [H]*[OH] and plug in the concentrations. Kw = (2.95 x 10^-8) * (2.95 x 10^-8) = 8.71 x 10^-16
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “At a certain temperature, the ph of a neutral solution is 7.64. what is the value of kw at that temperature? express your answer ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers