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5 February, 06:13

A balloon is filled with 35.0 L of helium in the morning when the temperature is 20.0C. By noon the temperature has risen to 45.0C. What is the new volume of the balloon?

A

2.5L

B

3.5L

C

4.5L

D

5.5L

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Answers (2)
  1. 5 February, 06:24
    0
    The question to your answer is: V2 = 78.75 l non if the options given

    Explanation:

    Data

    V1 = 35 l

    T1 = 20 °C

    T2 = 45°C

    V2 = ?

    Formula

    V1 / T1 = V2 / T2

    Clear V2 from the equation

    V2 = V1T2/T1

    Substitution

    V2 = (35) (45) / (20)

    V2 = 78.75 l
  2. 5 February, 06:40
    0
    The new volume of the balloon is 78.75 L

    Explanation:

    Charles's law relates the volume and temperature of an ideal gas, to a constant pressure, therefore we must use that ratio to calculate the final temperature, according to the data provided:

    Vinitial = 35 L

    Tinitial = 20ºC

    Vfinal = ?

    Tfinal = 45ºC

    Vfinal = (Vinitial x Tfinal) / Tinitial = (35 L x 45ºC) / 20ºC = 78.75 L
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