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5 February, 21:10

Liquid hexane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water. suppose 41. g of hexane is mixed with 150. g of oxygen. calculate the maximum mass of water that could be produced by the chemical reaction. round your answer to significant digits.

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  1. 5 February, 21:21
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    The balanced chemical equation for the reaction of hexane with O₂ is given below;

    2C₆H₁₄ + 19O₂ - - > 12CO₂ + 14H₂O

    Stoichiometry of hexane to oxygen is 2:19

    number of hexane moles - 41 g / 86.2 g/mol = 0.476 mol

    number of oxygen moles - 150 g / 32 g/mol = 4.69 mol

    we need to find which reagent is the limiting reactant

    If hexane is the limiting reactant

    2 moles of hexane reacts with - 19 mol of oxygen

    therefore 0.476 mol - 19/2 x 0.476 = 4.522 mol

    since 4.69 mol of oxygen is present, O₂ is in excess and hexane is the limiting reactant.

    stoichiometry of hexane to water is 2:14

    2 mol of hexane gives 14 mol of water

    therefore 0.476 mol of hexane forms - 14/2 x 0.476 - 3.33 mol

    mass of water formed - 3.33 mol x 18.0 g/mol = 59.9 g
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