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5 February, 13:34

Suppose that a newly discovered element called centium has 3 isotopes that occure in nature. These are centium - 200, centium - 203, and centium - 209. Assume that these isotopes occur in equal amounts in nature. What will be the average atomic mass of this element?

I'm super confused

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  1. 5 February, 13:42
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    The answer to your question is 203.8 g

    Explanation:

    Data

    Average atomic mass = ?

    Centium-200

    Centium-203

    Centium-209

    Equal amounts

    Process

    1. - Determine the abundance of each isotope.

    If they are in equal amounts in nature, just divide 100 by 3

    100/3 = 33.33 % or 0.333

    2. - Determine the Average atomic mass

    Average atomic mass = Atomic mass 1 x abundance + Atomic mass 2 x

    abundance + Atomic mass 3 x abundance

    - Substitution

    Average atomic mass = 200 x 0.333 + 203 x 0.333 + 209 x 0.333

    - Simplification

    Average atomic mass = 66.6 + 67.6 + 69.6

    Result

    Average atomic mass = 203.8 g
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