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25 August, 00:21

How many moles of phosphoric acid are required to neutralize 7.2 mol of potassium hydroxide?

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  1. 25 August, 00:44
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    2.4 Moles of Phosphoric acid are required to neutralize 7.2 moles of potassium hydroxide

    Explanation:

    Phosphoric acid = Formula: H3PO4

    Potassium hydroxide = Formula: KOH

    H3PO4 + 3KOH = K3PO4 + 3H2O

    Ratio 1:3

    7.2 mol Potassium hydroxide = Formula: KOH

    7.2/3 = 2.4 Mol Phosphoric acid = Formula: H3PO4
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