Determine the temperature (in K) of 1.5 moles of gas contained in a 5.5 L vessel at a pressure of 192.4 kPa.

84.96K

Explanation:

The following were obtained from the question:

n = 1.5 mole

V = 5.5L

P = 192.4 kPa = 192400Pa

Recall

101325Pa = 1atm

192400Pa = 192400/101325 = 1.9atm

R = 0.082atm. L/K / mol

T=?

We can obtain the temperature by applying the following:

PV = nRT

T = PV / nR

T = (1.9 x 5.5) / (1.5 x 0.082)

T = 84.96K