Arrange the compounds in order of decreasing solubility in water. a) 1-butanthiol b) 1-butanol c) 1,2-propanediol Answer by ordering the letters a-c as a string, e. g. acb, starting with the compound of highest solubility. The order of decreasing solubility is

Question

Winston Lowery

Chemistry

23 July, 02:31

Arrange the compounds in order of decreasing solubility in water. a) 1-butanthiol b) 1-butanol c) 1,2-propanediol Answer by ordering the letters a-c as a string, e. g. acb, starting with the compound of highest solubility. The order of decreasing solubility is

+1

Answers (1)

Know the Answer?

Tanya Chang · Answer 1

cba

Explanation:

Alcohols are soluble in water because of the presence of the - OH group which interacts with water by hydrogen bonding leading to the miscibility of low molecular weight alcohols with water.

The solubility of alcohols in water decreases as the length of the alkyl chain increases. Similarly, the more the number of - OH groups present, the greater the solubility bof the alcohol in water.

1-butanol contains less - OH groups than 1,2-propanediol as well as a longer alkyl chain hence 1-butanol is less soluble in water than 1,2-propanediol. Butanthiol has the least solubility in water because the - SH group forms weaker hydrogen bonds than the - OH group.