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23 September, 21:41

Consider the combustion reaction,

2C4H2+5O 2--->4 CO2+2H2O

where C2 H2 Hf = 227.4 kJ/mol), CO2 (Hf = - 393.5 kJ/mol), and H2 O (Hf = - 241.82 kJ/mol). What is the enthalpy of the reaction?

-2,512.4 kJ

-1,256.2 kJ

1,256.2 kJ

2,512.4 kJ

+4
Answers (1)
  1. 23 September, 22:02
    0
    The chemical reaction should be:

    2 C₂H₂ + 5 O₂ - - - > 4 CO₂ + 2 H₂O

    This is complete combustion of a hydrocarbon.

    We are also given with

    C₂H₂ Hf = 227.4 kJ/mol

    CO₂ Hf = - 393.5 kJ/mol

    H₂O Hf = - 241.82 kJ/mol

    The enthalpy of the reaction is

    4 (-393.5) + 2 (-241.82) - 2 (227.4) = - 2512.44 kJ/mol
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