1. A gas sample at a pressure of 5.00 atm has a volume of 3.00 L. If the gas pressure is changed to 760 mm Hg, what volume will the gas occupy?

V₂ = 15.00 atm

Explanation:

Given dа ta:

Initial pressure = 5.00 atm

Initial volume = 3.00 L

Final pressure = 760 mmHg (760/760 = 1 atm)

Final volume = ?

Solution:

P₁V₁ = P₂V₂

V₂ = P₁V₁ / P₂

V₂ = 5.00 atm * 3.00 L / 1 atm

V₂ = 15.00 atm