Exactly 253.0 J will raise the temperature of 10.0 g of a metal from 25.0 °C to 60.0 °C. What is the specific heat capacity of the metal?

a. 0.723 J / (g. °C)

b. 1.38 J / (g°C)

C 12.2 J/g °C)

d. 60.5J/g - °C)

e. None of these

Question

Regan Delacruz

Chemistry

21 August, 23:49

Exactly 253.0 J will raise the temperature of 10.0 g of a metal from 25.0 °C to 60.0 °C. What is the specific heat capacity of the metal?

a. 0.723 J / (g. °C)

b. 1.38 J / (g°C)

C 12.2 J/g °C)

d. 60.5J/g - °C)

e. None of these

+1

Answers (1)

Know the Answer?

Sariah Briggs · Answer 1

Answer:a. 0.723 J / (g. °C)

Explanation:

Q = mCΔT

where,

Q - Quantity of heat supplied- = 253.0j

m - mass of substance=10g

C - specific heat capacity=?

ΔT - change in temperature = 60 - 25 = 35°C

Imputing values, we have,

Q = mCΔT

C = Q / (mΔT) = 253.0 / (10 x 35) = 0.7228 rounded to - --> 0.723 J / (g. °C)

Exactly 253.0 J will raise the temperature of 10.0 g of a metal from 25.0 °C to 60.0 °C. What is the specific heat capacity of the metal?a. 0.723 J / (g. °C)b. 1.38 J / (g°C)C 12.2 J/g °C)d. 60.5J/g - °C)e. None of these

Exactly 253.0 J will raise the temperature of 10.0 g of a metal from 25.0 °C to 60.0 °C. What is the specific heat capacity of the metal?

a. 0.723 J / (g. °C)

b. 1.38 J / (g°C)

C 12.2 J/g °C)

d. 60.5J/g - °C)

e. None of these