What amount of ammonia, NH3 (g), can be produced from 15 mol of hydrogen reacting with excess nitrogen?

3 H2 (g) + N2 (g) → 2NH3 (g)

Question

Everett

Chemistry

17 March, 12:27

What amount of ammonia, NH3 (g), can be produced from 15 mol of hydrogen reacting with excess nitrogen?

3 H2 (g) + N2 (g) → 2NH3 (g)

+4

Answers (1)

Know the Answer?

Aracely Burns · Answer 1

10mol

Explanation:

3H2 + N2 - > 2NH3

Stoichiometry is a tool that chemists can use to find the amount of substance present in any part of a reaction. The arrow (->) suggests that the reaction goes to completion (100%), so assume that left side = right side.

3H2

15 mol

You can divide the amount of moles by the coefficient to find the number of moles when you have a coefficient of 1. This number can then be used to find the value of moles for the rest of the products/reactants:

15/3=5mol

NH3 has a coefficient of 2, so we have to multiply the value we got (5mol) by 2. This results in having 10mol of ammonia as the end result.

What amount of ammonia, NH3 (g), can be produced from 15 mol of hydrogen reacting with excess nitrogen?3 H2 (g) + N2 (g) → 2NH3 (g)

What amount of ammonia, NH3 (g), can be produced from 15 mol of hydrogen reacting with excess nitrogen?

3 H2 (g) + N2 (g) → 2NH3 (g)