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17 September, 10:07

If it takes 200 J to raise the temperature of a 10-gram block of ice by 10°C, what is the specific heat of the ice?

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  1. 17 September, 10:13
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    The specific heat of ice is 2 j/g. °C

    Explanation:

    Given dа ta:

    Amount of heat = 200 J

    Mass of ice = 10 g

    Temperature change = 10 °C

    Specific heat = ?

    Solution:

    Formula:

    Q = m. c. ΔT

    Q = amount of heat

    m = mass

    c = specific heat

    ΔT = change in temperature

    Now we will put the values in formula,

    Q = m. c. ΔT

    200 j = 10 g. c. 10 °C

    c = 200 j / 100 g. °C

    c = 2 j / g. °C

    The specific heat of ice is 2 j/g. °C.
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