An unbalanced chemical equation for the reaction of boron fluoride with lithium sulfite is shown below.

BF3 + LI SO3 → B2 (SO3) 3 + LIF

What is the coefficient of lithium fluoride in the balanced chemical reaction?

1

6

Explanation:

You have the unbalanced chemical reaction:

BF3 + Li2SO3 ⇒ B2 (SO3) 3 + LiF

Knowing that there are 2 atoms of boron in the products, we need to adjust that element putting 2 as coefficient of BF3.

2BF3 + Li2SO3 ⇒ B2 (SO3) 3 + LiF

Then, we need to balance fluor. There are 6 atoms of F in the reactants, for that reason, we write 6 in the lithium fluoride.

2BF3 + Li2SO3 ⇒ B2 (SO3) 3 + 6LiF

Finally, sulfur and oxygen have to be adjusted. 3 before lithium sulfite is enough to balance the chemical reaction.

2BF3 + 3Li2SO3 ⇒ B2 (SO3) 3 + 6LiF