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14 August, 06:33

What is the molarity of 0.945 L of a solution that contains 0.227 moles of Fe (NO3) 3?

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  1. 14 August, 06:54
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    0.2402 M

    Explanation:

    0.945 L sol contains = 0.227 moles

    1 L sol will contain = (0.227/0.945) * 1 = 0.2402 moles

    Molarity = 0.2402 moles/L or M
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