How much heat is needed to raise the temperature of 50.0 g of water from 4.5 ⁰C

to 83.0 ⁰C?

The heat needed to raise the temperature of 50.0 g of water from 4.5 ⁰C

to 83.0 ⁰C is 16.46KJ

Explanation:

To solve the problem,

we need the value of the water and its given by,

C=4.18 * J / g ∘ C

To increase the temperature we need m grams of water by n ∘ C

And the formula for the heat is given by, heat = m * n * specific

heat

q = m ⋅ c. Δ T

where q denotes the heat absorbed

m denotes the mass sample

c denotes the specific heat

Δ T denotes the change in the temperature

Based on the data it is written as,

q = 50.0 g. 4.18 J / g ∘ C (83.0-4.5) ∘ C

Simplifying the equation we get,

q=16406.5 J

Express it in the form of significant figure

16406.5 J. 1 KJ / 10^ 3 J

Solving the equation we get

16.46KJ

The heat needed to raise the temperature of 50.0 g of water from 4.5 ⁰C

to 83.0 ⁰C is 16.46 KJ