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30 November, 15:00

A standard solution is prepared for the analysis of fluoxymesterone (c20h29fo3; 336 g/mol), an anabolic steroid. a stock solution is first prepared by dissolving 16.8 mg of fluoxymesterone in enough water to give a total volume of 500.0 ml. a 1.0 μl aliquot (portion) of this stock solution is taken out and then diluted to a final volume of 1.0 ml. calculate the final concentration of this new solution in m.

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  1. 30 November, 15:07
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    The concentration of new solution will be 1*10∧-7 M.

    Solution:

    Data Given

    given mass of fluoxymesterone = 16.8mg = 0.0168 g

    molar mass of fluoxymesterone = 336g/mol

    vol. of fluoxymesterone = 500.0 ml = 0.500 L

    Stock Molarity of fluoxymesterone = (0.0168/336) : 0.500 = 1*10∧-4 M

    So applying dilution formula

    Stock Solution : New Solution

    M1. V1 = M2. V2

    (1*10∧-4 M) * (1*10∧-6 L) = M2 * 0.001 L

    [ (1*10∧-4) * (1*10∧-6) ]:[0.001] = M2

    1 * 10∧-7 = M2

    Result:

    The concentration of new solution M2 will be 1 * 10∧-7
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