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13 May, 09:56

The vapor pressure of water at 45oC is 71.88 mmHg. What is the vapor pressure of a sugar (C12H22O11) solution made by dissolving 50.36 g of sugar in 88.69 g of water

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  1. 13 May, 10:06
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    69.79 mmHg is the pressure for the solution

    Explanation:

    Formula for vapor pressure lowering:

    Vapor pressure of pure solvent (P°) - Vapor pressure of solution (P') = P°. Xm

    Xm → Molar fraction of solute (moles of solute / Total moles)

    Total moles = Moles of solute + Moles of solvent

    Let's determine the moles:

    50.36 g. 1mol/342 g = 0.147 moles of sugar

    88.69 g. 1mol / 18g = 4.93 moles of water

    Total moles = 0.147 + 4.93 = 5.077 moles

    Xm = 0.147 / 5.077 = 0.0289

    If we replace data given in the formula:

    71.88 mHg - P' = 71.88 mmHg. 0.0289. 0.0289

    P' = - (71.88 mmHg. 0.0289 - 71.88 mmHg)

    P' = 69.79 mmHg
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