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18 October, 09:31

Using an extinction coefficient of 15,000 M-1cm-1, calculate the concentration (in mM) of a molecule with an absorbance value of 0.200. You can assume the standard cuvette pathlength of 1 cm.

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  1. 18 October, 09:34
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    0.013 mM

    Explanation:

    Our strategy to solve this question will be to utilize Beer-Lambert law:

    A = ε c L where A is the absorbance,

    ε is the extinction coefficient (M⁻¹cm⁻1),

    c is the concentration (in M)

    L is the cuvette path length (in cm)

    so the concentration, c, from this equation will be given by

    c = A / (ε L)

    we have all the required values, thus

    c = 0.200 / (15000 M⁻¹ cm⁻1 x 1 cm) = 1.3 x 10⁻⁵ M

    Now we are being asked to give the concentration in mmol (1 mol = 1000 mmol) per liter, so we need to convert our concentration:

    1.3 x 10⁻⁵ mol/L x 1000 mmol/mol = 0.013 mmol/L = 0.013 mM
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