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11 April, 05:11

the volume of a gas is 550 ml at 960 mm hg and 200.0°C. What volume would the pressure of the gas be 830 mm Hg if the temperature is reduced to 150°C?

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  1. 11 April, 05:19
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    V₂ = 568.9 mL

    Explanation:

    Given dа ta:

    Volume of gas = 550 mL

    Pressure of a gas = 960 mmHg

    Temperature = 200.0°C (200+273 = 473 K)

    Final volume = ?

    Final pressure = 830 mmHg

    Final temperature = 150°C (150+273 = 423 K)

    Solution:

    Formula:

    P₁V₁/T₁ = P₂V₂/T₂

    P₁ = Initial pressure

    V₁ = Initial volume

    T₁ = Initial temperature

    P₂ = Final pressure

    V₂ = Final volume

    T₂ = Final temperature

    Solution:

    V₂ = P₁V₁ T₂ / T₁ P₂

    V₂ = 960 mmHg * 550 mL * 423 K / 473 K * 830 mmHg

    V₂ = 223344000 mL / 392590

    V₂ = 568.9 mL
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