In your lab you are studying the kinetics of the degradation of a pain killer in the human liver. You are monitoring the concentration of the pain killer over a period of time. The initial concentration of the pain killer in your experiment was 1.59 M. After 0.80881 hours the concentration was found to be 0.795 M. In another 0.80881 hours the concentration was found to be 0.3975 M (t=27.868 hours overall).

If another experiment were set up where the initial concentration of the pain killer was 0.479 M, how long would it take for the pain killer concentration to reach 0.0161 M?

Question

Axel Ross

Chemistry

26 December, 05:09

In your lab you are studying the kinetics of the degradation of a pain killer in the human liver. You are monitoring the concentration of the pain killer over a period of time. The initial concentration of the pain killer in your experiment was 1.59 M. After 0.80881 hours the concentration was found to be 0.795 M. In another 0.80881 hours the concentration was found to be 0.3975 M (t=27.868 hours overall).

If another experiment were set up where the initial concentration of the pain killer was 0.479 M, how long would it take for the pain killer concentration to reach 0.0161 M?

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Answers (1)

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Shaun Woodward · Answer 1

From the data it is clear that after each. 80881 hours, the concentration becomes half. so its decomposition appears to be first order.

k = 1 / t ln A₀ / A

= (1/.80881) ln 2

=.857

for the given case

A =.0161, A₀ =.479

t = ?

t = 1/k ln (.479 /.0161)

= (1 /.857) ln (.479 /.0161)

= (1 /.857) x ln 29.75

= 3.959 hours