How many moles of O_{2} molecules are present in a 0.301 L sample of dry air at 0.0395 atm and 23.8 °C? (Oxygen constitutes 20.94% of the molecules in dry air.) (Enter your answer using either standard or scientific notation. For scientific notation, 6.02 x 10^{23} is written as 6.02E23.)

Question

Jesse Durham

Chemistry

12 August, 07:12

How many moles of O_{2} molecules are present in a 0.301 L sample of dry air at 0.0395 atm and 23.8 °C? (Oxygen constitutes 20.94% of the molecules in dry air.) (Enter your answer using either standard or scientific notation. For scientific notation, 6.02 x 10^{23} is written as 6.02E23.)

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Answers (1)

Know the Answer?

Parker Bryant · Answer 1

The answer to your question is n = 4.89E-4

Explanation:

Data

Volume = 0.301 L

Pressure = 0.0395 atm

Temperature = 23.8 °C

moles = ?

R = 0.082 atm L / mol°K

Process

1. - Convert the temperature to °K

Temperature = 273 + 23.8

= 296.8°K

2. - Use the ideal gas law to find the answer

PV = nRT

-Solve for n

n = PV / RT

-Substitution

n = (0.0395) (0.301) / (0.082) (296.8)

-Simplification

n = 0.011889 / 24.3376

-Result

n = 0.000488 or n = 4.89 x 10⁻⁴ or n = 4.89E-4