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7 March, 01:59

For the reaction N₂ (g) + 3H₂ (g) ⇌ 2NH₃ (g) what is the value of Kc at 500 ∘C if the equilibrium concentrations are as follows:

[H₂] = 0.50 M, [N₂] = 0.50 M, and [NH₃] = 2.1 M?

Express the equilibrium constant to two significant figures.

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  1. 7 March, 02:19
    0
    Kc = 70

    Explanation:

    This is the reaction:

    N₂ (g) + 3H₂ (g) ⇌ 2NH₃ (g)

    Let's make the expression for K, with concentration at equilibrium and in molarity.

    Kc = [NH₃]² / [H₂]³. [N₂]

    Kc = (2.1) ² / (0.5) ³. 0.5

    Kc = 4.41 / 0.0625 → 70
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