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Kamren Marshall
Chemistry
11 June, 08:43
What is the pH of a 9.50*10-2 M ammonia solution?
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Ty Kirk
11 June, 08:48
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NH₃ + H₂O ⇄ NH₄⁺ + OH⁻
c=9,50*10⁻² mol/L
Ammonia solution is a weak electrolyte.
The dissociation constant of ammonium hydroxide is:
K=1.78*10⁻⁵
[OH⁻]=√ (Kc)
pH=14-pOH=14+lg[OH]⁻
pH=14+lg (√ (Kc))
pH=14+lg (√ (1.78*10⁻⁵*9.50*10⁻²)) = 8.23
pH=8.23
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