14 October, 07:51
Determine the percent yield for the reaction between 3.74 g of na and excess o2 if 5.34 g of na2o2 is recovered.
14 October, 08:46
Answer is: the percent yield for the reaction is 84,2%.
Chemical reaction: 2Na + O₂ → Na₂O₂.
m (Na) = 3,74 g.
n (Na) = m (Na) : M (Na).
n (Na) = 3,74 g : 23 g/mol.
n (Na) = 0,162 mol.
From chemical reaction: n (Na) : n (Na₂O₂) = 2 : 1.
n (Na₂O₂) = 0,162 mol : 2 = 0,081 mol.
m (Na₂O₂) = 0,081 mol · 78 g/mol.
m (Na₂O₂) = 6,341 g.
yield of reaction = 5,34 g / 6,341 g · 100%.
yield of reaction = 84,2%.
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» Determine the percent yield for the reaction between 3.74 g of na and excess o2 if 5.34 g of na2o2 is recovered.