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10 August, 03:31

How many moles of Al (CN) 3 are in 183 g of the compound?

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  1. 10 August, 03:56
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    You need to calculate the molar mass for Al (CN) 3 using the atomic weights for Al, C, and N given on the periodic table.

    1 Al (26.98) + 3 C (3 x 12.01) + 3 N (3 x 14.01) = 105.04 g Al (CN) 3 / mole

    183 g Al (CN) 3 x (1 mole Al (CN) 3 / 105.04 g Al (CN) 3) = 1.74 moles Al (CN) 3
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