How many moles of Al (CN) 3 are in 183 g of the compound?

Question

Helena Mcgrath

Chemistry

10 August, 03:31

How many moles of Al (CN) 3 are in 183 g of the compound?

+4

Answers (1)

Know the Answer?

Hill · Answer 1

You need to calculate the molar mass for Al (CN) 3 using the atomic weights for Al, C, and N given on the periodic table.

1 Al (26.98) + 3 C (3 x 12.01) + 3 N (3 x 14.01) = 105.04 g Al (CN) 3 / mole

183 g Al (CN) 3 x (1 mole Al (CN) 3 / 105.04 g Al (CN) 3) = 1.74 moles Al (CN) 3