A 0.821 gram sample of pure NH F was treated with 25.0 mL of 1.00 M NaOH

and heated to drive off the NH.

a. How many mols of NaOH are needed to react with the NH F?

0.0222 mole of NaOH is needed to react with NH4F

Explanation:

NH4F + NaOH - -> NaF + NH3 + H2O

Data given

Mass of NH4F = 0.821g, Concentration of NaOH = 1M, volume of NaoH = 25ml

But mole = (CV) / 1000

given mole of NaoH = (1 * 25) / 1000 = 0.025moles of NaOH used

Molar mass of NH4F = 37g/mol

mole of NH4F used 0.821 / 37 = 0.0222 mole NH4F

Determine the excess and limiting reactant,

NaOH is in excess

0.025 - 0.0222 = 0.0028 mole NaOH excess

0.0222 mole of NaOH is required to react with NH4F