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14 July, 09:56

There are 45,000 mg of nitrogen dioxide in a container at STP. What is the volume?

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  1. 14 July, 10:20
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    V = 22.86 L

    Explanation:

    Given dа ta:

    Mass of nitrogen dioxide = 45000 mg

    Pressure = 1 atm

    Temperature = 273 k

    Volume = ?

    Solution:

    First of all we will convert the mass into moles.

    Number of moles = mass / molar mass

    Number of moles = 45 g / 46 g/mol

    Number of moles = 1.02 mol

    Now we will determine the volume at STP.

    PV = nRT

    V = nRT/P

    V = 1.02 mol * 0.0821 atm. mol⁻¹. k⁻¹. L * 273 k / 1 atm

    V = 22.86 atm. L / 1 atm

    V = 22.86 L
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