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23 April, 12:57

How many moles of NH3NH3 can be produced from 13.5 molmol of H2H2 and excess N2N2? Express your answer numerically in moles.

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  1. 23 April, 12:59
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    Answer: 9 moles of NH3

    Explanation:

    N2 + 3H2 - > 2NH3

    From the equation,

    3 moles of H2 produced 2moles of NH3.

    Therefore, 13.5moles of H2 will produce = (13.5x2) / 3 = 9 moles of NH3
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