Ask Question
16 September, 17:06

Write a balanced equation for the dissolution of sodium carbonate (Na2CO3) in water. Find the number of moles of Na + produced when 0.207 mol of sodium carbonate dissolves.

+5
Answers (1)
  1. 16 September, 17:33
    0
    in the presence of water H2O

    Na2CO3 (S) - -> 2Na + (aq) + (CO3) 2 - (aq)

    One mole of sodium carbonate produces two moles of Na + ions

    Therefore 0.207 moles produces 0.414 moles of Na + ions

    = 0.414 moles of Na + ions

    Explanation:

    In water

    Na2CO3 - -> 2Na + (aq) + (CO3) 2 - (aq)

    In a limited reaction, the carbonate ion reacts with the water molecules as follows

    (CO3) 2 - (aq) + H2O←→HCO3 - (aq) + OH - (aq)

    sodium carbonate or soda ash dissolves in water to give 2 sodium cations and one carbonate anion
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Write a balanced equation for the dissolution of sodium carbonate (Na2CO3) in water. Find the number of moles of Na + produced when 0.207 ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers