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Today, 11:58

How many moles of KCl will be

produced from 15.0 g of KClO3?

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Answers (2)
  1. Today, 12:21
    0
    0.1224 moles

    Explanation:

    this is a decompostion reaction

    Equation of reaction

    2KClO₃ → 2KCl + 3O₂

    molar mass of KClO₃ =

    molar mass of K = 39.09g/mol

    Molar mass of Cl = 35.5g/mol

    Molar mass of O = 15.99g/mol

    Molar mass of KClO3 = [39 + 35.5 + (3*15.99) ]

    Molar mass of KClO3 = 122.47g/mol

    From the equation of reaction,

    2 moles of KClO₃ produces 2 moles of KClO₃

    But 1 mole = molar mass

    1 mole of KClO₃ = 122.47g

    2 moles of KClO₃ = 2 * 122.47 = 244.94g

    If 244.94g of KClO₃ produces 2 moles of KCl

    15 g of KClO₃ will produce x mole of KCl

    x = (15 * 2) / 244.94

    x = 0.1224moles

    15g of KClO₃ will produce 0.1224moles of KCl
  2. Today, 12:25
    0
    0.12 mol KCl

    Explanation:

    2 KClO3 (s) 2 KCl (s) + 3 O2 (g)

    15 g x mol

    x g KCl = 15 g KClO3 x[ (1 mol KClO3) / (122.5 g KClO3) ] x [ (2 mol KCl) / (2 mol KClO3) ]

    x g KCl = 0.12 mol KCl
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