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6 January, 17:09

43.0 grams of potassium chloride dissolves in 600 mL of water. What is the concentration of the solution?

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Answers (2)
  1. 6 January, 17:11
    0
    Answer: 0.96M

    Explanation:

    Potassium chloride has a chemical formula of KCl.

    Mass of KCl = 43.0 grams

    Amount of moles of KCl (n) = ?

    Use the molar mass of KCl to get the amount in moles.

    The atomic masses of Potassium = 39g;

    and Chlorine = 35.5g

    So, KCl = 39g + 35.5g

    = 74.5g/mol

    Then, apply the formula

    Number of moles = mass in grams / molar mass

    n = 43.0g / 74.5 g/mol

    n = 0.577 moles

    Now, given that

    Volume of water (v) = 600mL

    [convert 600mL to liters

    If 1000mL = 1 liter

    600mL = 600/1000 = 0.6 liters]

    Concentration of solution (c) = ?

    Amount of moles of KCl (n) =

    Since concentration (c) is obtained by dividing the amount of solute dissolved by the volume of solvent, hence

    c = n / v

    c = 0.577 moles / 0.6 liters

    c = 0.96M

    Thus, the concentration of the solution is acidic 0.96M
  2. 6 January, 17:28
    0
    0,9613 mol/dm^3

    Explanation:

    Molarmass of KCl is 74,55 g/mol. So 43grams of it is 43/74,55=0,5768 mol.

    Density of water is ususally 1g/cm^3. So 600ml=600cm^3=0,6dm^3.

    You have 0,5768 mol of stuff in 0,6dm^3 water. If the question refers to conventional mol/cm^3 concentration, then you need to find out how much stuff is in 1dm^3 water, you do that by (1/0,6) * 0,5768=0,96133
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