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16 August, 08:02

Approximately 3.54 kJ were used to heat a pot of potato soup, from 25 degrees * C to 100 degrees * C. If the specific heat of potatoes is 3.67 J/g^ C how many grams of potatoes were cooked?

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  1. 16 August, 08:23
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    12.9 g potatoes

    Explanation:

    Given dа ta:

    Amount of heat used = 3.54 Kj

    Initial temperature = 25°C

    Final temperature = 100°C

    Specific heat capacity of potatoes = 3.67 j/g.°C

    Solution:

    Formula:

    Q = m. c. ΔT

    Q = amount of heat absorbed or released

    m = mass of given substance

    c = specific heat capacity of substance

    ΔT = change in temperature

    ΔT = T2 - T1

    ΔT = 100°C - 25°C

    ΔT = 75°C

    Q = m. c. ΔT

    m = Q / c. ΔT

    m = 3540 j / 3.67 j/g.°C * 75°C

    m = 3540 j / 275.25 j/g

    m = 12.9 g
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